RosettaCodeData/Task/Sort-numbers-lexicographically/Julia/sort-numbers-lexicographically.jl
2024-10-16 18:07:41 -07:00

5 lines
163 B
Julia

lexorderedsequence(n) = sort(collect(n > 0 ? (1:n) : n:1), lt=(a,b) -> string(a) < string(b))
for i in [0, 5, 13, 21, -32]
println(lexorderedsequence(i))
end