20 lines
541 B
Julia
20 lines
541 B
Julia
function superellipse(n, a, b, step::Int=100)
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@assert n > 0 && a > 0 && b > 0
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na = 2 / n
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pc = 2π / step
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t = 0
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xp = Vector{Float64}(undef, step + 1)
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yp = Vector{Float64}(undef, step + 1)
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for i in 0:step
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# because sin^n(x) is mathematically the same as (sin(x))^n...
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xp[i+1] = abs((cos(t))) ^ na * a * sign(cos(t))
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yp[i+1] = abs((sin(t))) ^ na * b * sign(sin(t))
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t += pc
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end
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return xp, yp
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end
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using UnicodePlots
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x, y = superellipse(2.5, 200, 200)
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println(lineplot(x, y))
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