RosettaCodeData/Task/Arbitrary-precision-integers--included-/Python/arbitrary-precision-integers--included-.py

>>> y = str( 5**4**3**2 )
>>> print ("5**4**3**2 = %s...%s and has %i digits" % (y[:20], y[-20:], len(y)))
5**4**3**2 = 62060698786608744707...92256259918212890625 and has 183231 digits
	`>>> y = str( 543**2 )`
	`>>> print ("543**2 = %s...%s and has %i digits" % (y[:20], y[-20:], len(y)))`
	`543**2 = 62060698786608744707...92256259918212890625 and has 183231 digits`