RosettaCodeData/Task/Fibonacci-sequence/Haskell/fibonacci-sequence-17.hs
2018-06-22 20:57:24 +00:00

1 line
78 B
Haskell

f (n,(a,b)) = (2*n,(a*a+b*b,2*a*b+b*b)) -- iterate f (1,(0,1)) ; b is nth