RosettaCodeData/Task/Middle-three-digits/C/middle-three-digits-2.c
2014-01-17 05:34:36 +00:00

56 lines
1.3 KiB
C

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void midThree(char arg[])
{
char output[4];
int midPoint;
arg[0]=='-'?midPoint = ((strlen(arg) + 1) / 2):midPoint = ((strlen(arg) + 1) / 2) - 1;
if(strlen(arg) < 3)
{
printf("Error, %d is too short.\n",atoi(arg));
return ;
}
else if(strlen(arg) == 4 || strlen(arg) == 3)
{
printf("Error, %d has %d digits, no 3 middle digits.\n",atoi(arg),arg[0]=='-'?strlen(arg)-1:strlen(arg));
return ;
}
else{
for(int i=0; i<3; i++)
{
output[i] = arg[(midPoint-1) + i];
}
output[3] = '\0';
printf("The middle three digits of %s are %s.\n",arg,output);
}}
int main(int argc, char * argv[])
{
char input[50];
int x[] = {123, 12345, 1234567, 987654321, 10001, -10001,
-123, -100, 100, -12345, 1, 2, -1, -10, 2002, -2002, 0,
1234567890},i;
if(argc < 2)
{
printf("Usage: %s <integer>\n",argv[0]);
printf("Examples with preloaded data shown below :\n");
for(i=0;i<18;i++)
{
midThree(itoa(x[i],argv[0],10));
}
return 1;
}
else
{
sprintf(input,"%d",atoi(argv[1]));
midThree(argv[1]);
return 0;
}
}