RosettaCodeData/Task/Reverse-a-string/Lingo/reverse-a-string-2.lingo
2016-12-05 23:44:36 +01:00

8 lines
162 B
Text

on reverseBytes (str)
ba = byteArray(str)
res = byteArray()
repeat with i = ba.length down to 1
res[res.length+1] = ba[i]
end repeat
return res
end