RosettaCodeData/Task/Thieles-interpolation-formula/D/thieles-interpolation-formula.d
2015-02-20 00:35:01 -05:00

72 lines
2.3 KiB
D

import std.stdio, std.range, std.array, std.algorithm, std.math;
struct Domain {
const real b, e, s;
auto range() const pure /*nothrow*/ @safe /*@nogc*/ {
return iota(b, e + s, s);
}
}
real eval0(alias RY, alias X, alias Y)(in real x) pure nothrow @safe @nogc {
real a = 0.0L;
foreach_reverse (immutable i; 2 .. X.length - 3)
a = (x - X[i]) / (RY[i] - RY[i-2] + a);
return Y[1] + (x - X[1]) / (RY[1] + a);
}
immutable struct Thiele {
immutable real[] Y, X, rhoY, rhoX;
this(real[] y, real[] x) immutable pure nothrow /*@safe*/
in {
assert(x.length > 2, "at leat 3 values");
assert(x.length == y.length, "input arrays not of same size");
} body {
this.Y = y.idup;
this.X = x.idup;
rhoY = rhoN(Y, X);
rhoX = rhoN(X, Y);
}
this(in real function(real) pure nothrow @safe @nogc f,
Domain d = Domain(0.0L, 1.55L, 0.05L))
immutable pure /*nothrow @safe*/ {
auto xrng = d.range.array;
this(xrng.map!f.array, xrng);
}
auto rhoN(immutable real[] y, immutable real[] x)
pure nothrow @safe {
immutable int N = x.length;
auto p = new real[][](N, N);
p[0][] = y[];
p[1][0 .. $ - 1] = (x[0 .. $-1] - x[1 .. $]) /
(p[0][0 .. $-1] - p[0][1 .. $]);
foreach (immutable int j; 2 .. N - 1) {
immutable M = N - j - 1;
p[j][0..M] = p[j-2][1..M+1] + (x[0..M] - x[j..M+j]) /
(p[j-1][0 .. M] - p[j-1][1 .. M+1]);
}
return p.map!q{ a[1] }.array;
}
alias eval = eval0!(rhoY, X, Y);
alias inverse = eval0!(rhoX, Y, X);
}
void main() {
// Can't pass sin, cos and tan directly.
immutable tsin = Thiele(x => x.sin);
immutable tcos = Thiele(x => x.cos);
immutable ttan = Thiele(x => x.tan);
writefln(" %d interpolating points\n", tsin.X.length);
writefln("std.math.sin(0.5): %20.18f", 0.5L.sin);
writefln(" Thiele sin(0.5): %20.18f\n", tsin.eval(0.5L));
writefln("*%20.19f library constant", PI);
writefln(" %20.19f 6 * inv_sin(0.5)", tsin.inverse(0.5L) * 6.0L);
writefln(" %20.19f 3 * inv_cos(0.5)", tcos.inverse(0.5L) * 3.0L);
writefln(" %20.19f 4 * inv_tan(1.0)", ttan.inverse(1.0L) * 4.0L);
}