36 lines
1 KiB
Lua
36 lines
1 KiB
Lua
N = 2
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lst = { { "Tyler Bennett","E10297",32000,"D101" },
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{ "John Rappl","E21437",47000,"D050" },
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{ "George Woltman","E00127",53500,"D101" },
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{ "Adam Smith","E63535",18000,"D202" },
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{ "Claire Buckman","E39876",27800,"D202" },
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{ "David McClellan","E04242",41500,"D101" },
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{ "Rich Holcomb","E01234",49500,"D202" },
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{ "Nathan Adams","E41298",21900,"D050" },
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{ "Richard Potter","E43128",15900,"D101" },
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{ "David Motsinger","E27002",19250,"D202" },
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{ "Tim Sampair","E03033",27000,"D101" },
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{ "Kim Arlich","E10001",57000,"D190" },
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{ "Timothy Grove","E16398",29900,"D190" }
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}
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dep = {}
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for i = 1, #lst do
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if dep[ lst[i][4] ] == nil then
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dep[ lst[i][4] ] = {}
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dep[ lst[i][4] ][1] = lst[i]
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else
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dep[ lst[i][4] ][#dep[lst[i][4]]+1] = lst[i]
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end
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end
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for i, _ in pairs( dep ) do
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table.sort( dep[i], function (a,b) return a[3] > b[3] end )
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print( "Department:", dep[i][1][4] )
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for l = 1, math.min( N, #dep[i] ) do
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print( "", dep[i][l][1], dep[i][l][2], dep[i][l][3] )
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end
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print ""
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end
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