RosettaCodeData/Task/Hamming-numbers/Haskell/hamming-numbers-3.hs
2023-07-01 13:44:08 -04:00

2 lines
87 B
Haskell

hammFrom n = drop n $
iterate (\(_ , (a:t)) -> (a, union t [2*a,3*a,5*a])) (0, [1])