RosettaCodeData/Task/Ordered-words/Python/ordered-words-3.py
Ingy döt Net 86c034bb8b new files
2013-04-10 12:38:42 -07:00

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Python

from itertools import groupby
o = (w for w in map(str.strip, open("unixdict.txt")) if sorted(w)==list(w))
print list(next(groupby(sorted(o, key=len, reverse=True), key=len))[1])